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Subject: Polynomial
Replies: 2 Views: 446

fanking 22.05.10 - 11:22pm
ThE cubic polynomial f(x) is such that the coefficient of x3 is -1 and the roots of the equation f(x) = 0 are 1, 2 and k. given that f(x) has a remainder of 8 when divided by x - 3, find.
i)the value of k,
*

akushika 12.07.10 - 01:04pm
f(x)=(x-1)(x-2)(x& *

akushika 12.07.10 - 01:28pm
f(x)=(x-1)(x-2)(x-k)_f(x)=x3-3x2+2x-kx2+3xk-2k_f(x)=x3-3x2-2x-2k_f(x)=x3-[3+k]x2+2x-2k_divisor=x-3=0_x=3_f(x)=3*3*3-(3-k)3*3+2*3-2k_f(3)=27-27-9k-6-2k=8_-11k-6=8_k=-14/11 *

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